JEE Main 2022MathematicsInverse Trigonometric FunctionsMediumMCQ

JEE Main 2022 — Inverse Trigonometric Functions Question with Solution

JEE Main 2022 (27 Jun Shift 2)

Question

The value of cot∑n=150tan-111+n+n2 is

Choose an option

Show full solutionCorrect option: C
Correct answer
C2625

Step-by-step explanation

Now ∑n=150tan-111+n+n2=∑n=150tan-1n+1-n1+nn+1

=∑n=150tan-1n+1-tan-1n

=tan-151-tan-11=tan-151-11+51

=tan-15052=cot-12625

So cot∑n=150tan-111+n+n2=cotcot-12625=2625

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About this question

This is a previous-year question from JEE Main 2022, covering the Inverse Trigonometric Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.