JEE Main 2019MathematicsInverse Trigonometric FunctionsMediumMCQ

JEE Main 2019 — Inverse Trigonometric Functions Question with Solution

JEE Main 2019 (12 Apr Shift 1)

Question

The value of sin-1⁡1213-sin-1⁡35 is equal to:

Choose an option

Show full solutionCorrect option: D
Correct answer
Dπ2-sin-1⁡5665

Step-by-step explanation

sin-1⁡1213-sin-1⁡35
=tan-1⁡125-tan-1⁡34  sin-1⁡x=tan-1⁡x1-x2
=tan-1⁡125-341+12×35×4
=tan-1⁡3356
=sin-1⁡3365
=cos-1⁡5665=π2-sin-1⁡5665

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About this question

This is a previous-year question from JEE Main 2019, covering the Inverse Trigonometric Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.