JEE Main 2025 — Limits Question with Solution
JEE Main 2025 (29 Jan Shift 1)
Question
Let [t] be the greatest integer less than or equal to t. Then the least value of for which is equal to ________.
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Show full solutionCorrect answer: 24
Correct answer
24
Step-by-step explanation
$\begin{aligned}
& \frac{p(p+1)}{2}-\frac{9.10 .19}{6} \geq 1 \\
& p(p+1) \geq 572
\end{aligned}$
Least natural value of is 24
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This is a previous-year question from JEE Main 2025, covering the Limits chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.