JEE Main 2020MathematicsMatricesMediumNumerical

JEE Main 2020 — Matrices Question with Solution

JEE Main 2020 (03 Sep Shift 1)

Question

Let A=x110, x ε R and A4=aij. If a11=109, then a22 is equal to_____________.

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Show full solutionCorrect answer: 10
Correct answer
10

Step-by-step explanation

A2=x110×x110=x2+1xx1

A4=x2+1xx1×x2+1xx1=x4+3x2+1x3+2xx3+2xx2+1

Given a11=109⇒x4+3x2+1=109

x2+12x2-9=0⇒x2=9

∴a22=x2+1=10

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About this question

This is a previous-year question from JEE Main 2020, covering the Matrices chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.