JEE Main 2019 — Parabola Question with Solution
From: JEE Main 2019 (Online) 12th January Morning Slot
Question
The maximum area (in sq. units) of a rectangle having its base on the x-axis and its other two vertices on the parabola, y = 12 – x2 such that the rectangle lies inside the parabola, is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D32
Step-by-step explanation
f (a) = 2a(12 a)2
f '(a) = 2(12 3a2)
Maximum at a = 2
maximum area = f(2) = 32
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This is a previous-year question from JEE Main 2019, covering the Parabola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.