JEE Main 2018 — Parabola Question with Solution
From: JEE Main 2018 (Online) 15th April Evening Slot
Question
Tangents drawn from the point (8, 0) to the parabola y2 = 8x touch the parabola at and If F is the focus of the parabola, then the area of the triangle PFQ (in sq. units) is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C48
Step-by-step explanation
Equation of the chord of contact PQ is given by : T=0
or T yy1 4(x + x1), where (x1, y1) (8, 0)
Equation becomes : x = 8
& chord of contact is x = 8
Coordinates of point P and Q are (8, 8) and (8, 8)
and focus of the parabola is F (2, 0)
Area of triangle PQF = (8 2) (8 + 8) = 48 sq. units
or T yy1 4(x + x1), where (x1, y1) (8, 0)
Equation becomes : x = 8
& chord of contact is x = 8
Coordinates of point P and Q are (8, 8) and (8, 8)
and focus of the parabola is F (2, 0)
Area of triangle PQF = (8 2) (8 + 8) = 48 sq. units
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