JEE Main 2017MathematicsPermutation CombinationMediumMCQ

JEE Main 2017Permutation Combination Question with Solution

JEE Main 2017 (02 Apr)

Question

A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4 are men. Assume X and Y have no common friends. Then the total number of ways in which X and Y together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of X and Y are in this party is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A485

Step-by-step explanation

Here, m - men and L - ladies



Total=9×16+1+9×36+16

=144+1+324+16

=485

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About this question

This is a previous-year question from JEE Main 2017, covering the Permutation Combination chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.