JEE Main 2019MathematicsPermutation CombinationMediumMCQ

JEE Main 2019 — Permutation Combination Question with Solution

JEE Main 2019 (10 Apr Shift 1)

Question

The number of 6 digit number that can be formed using the digits 0, 1, 2, 5, 7 and 9 which are divisible by 11 and no digit is repeated is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B60

Step-by-step explanation

Only one possibility is there, (9,1,2) or (0,5,7) as in even or odd places
∴ Total number of required 6 digit numbers

=(9,1,2 in odd and 0,5,7 in even places)+(9,1,2 in even places and 0,5,7 in odd places)
=3!×3!+3! –2×3!
=36+24
=60

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About this question

This is a previous-year question from JEE Main 2019, covering the Permutation Combination chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.