JEE Main 2018MathematicsPermutation CombinationMediumMCQ

JEE Main 2018 — Permutation Combination Question with Solution

JEE Main 2018 (16 Apr Online)

Question

The number of numbers between 2,000 and 5,000 that can be formed with the digits 0, 1, 2, 3, 4 (repetition of digits is not allowed) and are multiple of 3 is

Choose an option

Show full solutionCorrect option: A
Correct answer
A36

Step-by-step explanation

When a number is divisible by 3, then sum of digits of a number is also divisible by 3.

Number can be formed from (0,1,2,3) or (0,2,3,4).

Number of 4 digits number

=3×3×2×1+3×3×2×1

=36.

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About this question

This is a previous-year question from JEE Main 2018, covering the Permutation Combination chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.