JEE Main 2026 — Quadratic Equation Question with Solution
JEE Main 2026 (24 January Shift 2)
Question
The smallest positive integral value of , for which all the roots of are real and distinct, is equal to
Choose an option
Show full solutionCorrect option: D
Correct answer
D7
Step-by-step explanation
Let , so the equation becomes .
For all four roots of the original equation to be real and distinct, both roots of this quadratic must be positive and distinct.
Discriminant : . Since , we need .
Product of roots and sum of roots , so both roots are positive.
The smallest positive integer satisfying is .
For all four roots of the original equation to be real and distinct, both roots of this quadratic must be positive and distinct.
Discriminant : . Since , we need .
Product of roots and sum of roots , so both roots are positive.
The smallest positive integer satisfying is .
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This is a previous-year question from JEE Main 2026, covering the Quadratic Equation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.