JEE Main 2022MathematicsSequences And SeriesGeometric ProgressionmediumNumerical

JEE Main 2022Sequences And Series Question with Solution

From: JEE Main 2022 (Online) 26th June Evening Shift

Question

If a1 (> 0), a2, a3, a4, a5 are in a G.P., a2 + a4 = 2a3 + 1 and 3a2 + a3 = 2a4, then a2 + a4 + 2a5 is equal to ___________.

Enter your answer

Show full solutionCorrect answer: 40
Correct answer
40

Step-by-step explanation

Let G.P. be a1 = a, a2 = ar, a3 = ar2, .........

3a2 + a3 = 2a4

3ar + ar2 = 2ar3

2ar2 r 3 = 0

r = 1 or

a1 = a > 0 then r 1

Now, a2 + a4 = 2a3 + 1

ar + ar3 = 2ar2 + 1

a =

a2 + a4 + 2a5 = a(r + r3 + 2r4)

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Sequences And Series chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Sequences And Series chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.