JEE Main 2023 — Sequences And Series Question with Solution
From: JEE Main 2023 (Online) 30th January Morning Shift
Question
Let \sum_\limits{n=0}^{\infty} \frac{\mathrm{n}^{3}((2 \mathrm{n}) !)+(2 \mathrm{n}-1)(\mathrm{n} !)}{(\mathrm{n} !)((2 \mathrm{n}) !)}=\mathrm{ae}+\frac{\mathrm{b}}{\mathrm{e}}+\mathrm{c}, where and e=\sum_\limits{\mathrm{n}=0}^{\infty} \frac{1}{\mathrm{n} !} Then is equal to ____________.
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Show full solutionCorrect answer: 26
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This is a previous-year question from JEE Main 2023, covering the Sequences And Series chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.