JEE Main 2019 — Sequences And Series Question with Solution
From: JEE Main 2019 (Online) 10th April Morning Slot
Question
If a1, a2, a3, ............... an are in A.P. and a1 + a4 + a7 + ........... + a16 = 114, then a1 + a6 + a11 + a16 is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C76
Step-by-step explanation
3(a1 + a16) = 114
Now a1 + a6 + a11 + a16 = 2(a1 + a16)
= 2 × 38 = 76
Now a1 + a6 + a11 + a16 = 2(a1 + a16)
= 2 × 38 = 76
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This is a previous-year question from JEE Main 2019, covering the Sequences And Series chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.