JEE Main 2017 — Sequences And Series Question with Solution
From: JEE Main 2017 (Offline)
Question
For any three positive real numbers a, b and c,
9(25 + b2) + 25(c2 - 3c) = 15b(3 + c).
Then
9(25 + b2) + 25(c2 - 3c) = 15b(3 + c).
Then
Choose an option
Show full solutionCorrect option: B
Correct answer
Bb, c and are in A.P.
Step-by-step explanation
9(25 + b2) + 25(c2 - 3c) = 15b(3 + c)
it is possible when 15a – 3b = 0, 3b – 5 c = 0 and 5c – 15a = 0
15a = 3b = 5c
b = , a =
a + b = = = 2c
b, c, a are in A.P.
it is possible when 15a – 3b = 0, 3b – 5 c = 0 and 5c – 15a = 0
15a = 3b = 5c
b = , a =
a + b = = = 2c
b, c, a are in A.P.
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This is a previous-year question from JEE Main 2017, covering the Sequences And Series chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.