JEE Main 2021 — Sequences And Series Question with Solution
From: JEE Main 2021 (Online) 16th March Evening Shift
Question
Sn(x) = loga1/2x + loga1/3x + loga1/6x + loga1/11x + loga1/18x + loga1/27x + ...... up to n-terms, where a > 1. If S24(x) = 1093 and S12(2x) = 265, then value of a is equal to ____________.
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Show full solutionCorrect answer: 16
Correct answer
16
Step-by-step explanation
Tn = 2 + (1 + 3 + 5 +......+ (n - 1))
= 2 +
= 2 +
= n2 - 2n + 3
General term
.....(i)
....(ii)
From (i) and (ii), we get
16 = 2
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This is a previous-year question from JEE Main 2021, covering the Sequences And Series chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.