JEE Main 2022MathematicsSets and RelationsMediumNumerical

JEE Main 2022 — Sets and Relations Question with Solution

JEE Main 2022 (28 Jun Shift 1)

Question

Let A=1,a1,a2……a18,77 be a set of integers with 1<a1<a2<…..<a18<77. Let the set A+A=x+y:x,y∈A contain exactly 39 elements. Then, the value of a1+a2+…..+a18 is equal to ______.

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Show full solutionCorrect answer: 702
Correct answer
702

Step-by-step explanation

If we write the elements of , we can certainly find 39 distinct elements as . It means all other sums are already present in these 39 values, which is only possible in case when all numbers are in A.P. Let the common difference be ' '. So,

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About this question

This is a previous-year question from JEE Main 2022, covering the Sets and Relations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.