JEE Main 2021 — Statistics Question with Solution
From: JEE Main 2021 (Online) 22th July Evening Shift
Question
Consider the following frequency distribution :
If mean = and median = 14, then the value (a b)2 is equal to _____________.
| Class : | 0-6 | 6-12 | 12-18 | 18-24 | 24-30 |
|---|---|---|---|---|---|
| Frequency : | 12 | 9 | 5 |
If mean = and median = 14, then the value (a b)2 is equal to _____________.
Enter your answer
Show full solutionCorrect answer: 4
Correct answer
4
Step-by-step explanation
| Class | Frequency | ||
|---|---|---|---|
| 0-6 | a | 3 | 3a |
| 6-12 | b | 9 | 9b |
| 12-18 | 12 | 15 | 180 |
| 18-24 | 9 | 21 | 189 |
| 24-30 | 5 | 27 | 135 |
Mean =
(1)
Now, Median
(2)
From equation (1) $ (2)
a = 8, b = 10
$${(a - b)^2} = {(8 - 10)^2}$ = 4
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This is a previous-year question from JEE Main 2021, covering the Statistics chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.