JEE Main 2019 — Statistics Question with Solution
From: JEE Main 2019 (Online) 10th April Evening Slot
Question
If both the mean and the standard deviation of 50 observations x1, x2,..., x50 are equal to 16, then the mean of (x1 – 4)2
, (x2 – 4)2
,....., (x50 – 4)2
is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A400
Step-by-step explanation
Required mean =
256 2 + 16 - 8 16
400
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This is a previous-year question from JEE Main 2019, covering the Statistics chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.