JEE Main 2020MathematicsStatisticsCalculation Of Standard Deviation Variance And Mean Deviation Of Grouped And Ungrouped DatamediumMCQ

JEE Main 2020Statistics Question with Solution

From: JEE Main 2020 (Online) 8th January Morning Slot

Question

The mean and the standard deviation (s.d.) of 10 observations are 20 and 2 resepectively. Each of these 10 observations is multiplied by p and then reduced by q, where p 0 and q 0. If the new mean and new s.d. become half of their original values, then q is equal to

Choose an option

Show full solutionCorrect option: B
Correct answer
B-20

Step-by-step explanation

Let observations are x1, x2, ...., x10

Here mean = 20 and standard deviation(S.D) = 2

When each of these 10 observations is multiplied by p then new observations are px1, px2, ....., px10
and new mean = 20p and new standard deviation(S.D) = 2|p|

Now when Reduced by q then new observations are
px1 - q, px2 - q, ....., px10 - q

and new mean = 20p - q and new standard deviation(S.D) = 2|p|

Given 20p - q = = 10
and 2|p| = = 1

p =

If p = then q = 0 (not possible as given q 0)

If p = - then q = -20

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About this question

This is a previous-year question from JEE Main 2020, covering the Statistics chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.