JEE Main 2016 — Statistics Question with Solution
From: JEE Main 2016 (Online) 9th April Morning Slot
Question
If the mean deviation of the numbers 1, 1 + d, ..., 1 +100d from their mean is 255, then a value of d is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A10.1
Step-by-step explanation
Given numbers are,
1, 1 + d, 1 + 2d . . . . . 1 + 100d
Total 101 number are present.
n = 101
mean =
= [1 + (1 + 100d)]
= 1 + 50d
Mean deviation from mean
=
= ( 1 + 2 + 3 + . . . . . + 50)
=
=
From question,
= 255
= 10.1
1, 1 + d, 1 + 2d . . . . . 1 + 100d
Total 101 number are present.
n = 101
mean =
= [1 + (1 + 100d)]
= 1 + 50d
Mean deviation from mean
=
= ( 1 + 2 + 3 + . . . . . + 50)
=
=
From question,
= 255
= 10.1
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Statistics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2016, covering the Statistics chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.