JEE Main 2021MathematicsThree Dimensional GeometryMediumMCQ

JEE Main 2021Three Dimensional Geometry Question with Solution

JEE Main 2021 (25 Feb Shift 1)

Question

The equation of the line through the point 0,1,2 and perpendicular to the line x-12=y+13=z-1-2 is :

Choose an option

Show full solutionCorrect option: C
Correct answer
Cx-3=y-14=z-23

Step-by-step explanation

x-12=y+13=z-1-2=r

 Px,y,z=2r+1,3r-1,-2r+1

Since, QP2i^+3j^-2k^

 4r+2+9r-6+4r+2=0

 r=217

 P2117,-1117,1317

 PQ=21i^-28j^-21k^17

So, QP:x-3=y-14=z-23

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Three Dimensional Geometry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Three Dimensional Geometry chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.