JEE Main 2023MathematicsTrigonometric Ratios & IdentitiesEasyNumerical

JEE Main 2023 — Trigonometric Ratios & Identities Question with Solution

JEE Main 2023 (06 Apr Shift 2)

Question

The value of  tan9o-tan27o-tan63o+tan81o is _____.

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Show full solutionCorrect answer: 4
Correct answer
4

Step-by-step explanation

Given,

tan9o-tan27o-tan63o+tan81o

=cot81°+tan81o-tan27°+cot27o

=tan9°+cot9°-tan27°+cot27°

=sin9°cos9°+cos9°sin9°-sin27°cos27°+cos27°sin27°

=2sin18o-2sin54o

=2×45-1-2×45+1

=815-1-15+1

=85+1-5-15-15+1

=825-1=4

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About this question

This is a previous-year question from JEE Main 2023, covering the Trigonometric Ratios & Identities chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.