JEE Main 2021MathematicsTrigonometric Ratios & IdentitiesMediumMCQ

JEE Main 2021 — Trigonometric Ratios & Identities Question with Solution

JEE Main 2021 (25 Jul Shift 2)

Question

The value of cotπ24 is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B2+3+2+6

Step-by-step explanation

We know that cotθ=1+cos2θsin2θ

Since, θ=π24

Therefore, cotθ=1+3+1223-122

⇒cotπ24=1+3+1223-122

=22+3+13-1×3+13+1

=26+22+3+3+3+12

=6+2+3+2.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Trigonometric Ratios & Identities chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Trigonometric Ratios & Identities chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.