JEE Main 2021 — Alternating Current Question with Solution
From: JEE Main 2021 (Online) 25th July Morning Shift
Question
An inductor of 10 mH is connected to a 20V battery through a resistor of 10 k and a switch. After a long time, when maximum current is set up in the circuit, the current is switched off. The current in the circuit after 1 s is mA. Then x is equal to ___________. (Take e1 = 0.37)
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Show full solutionCorrect answer: 74
Correct answer
74
Step-by-step explanation
mA
For LR - decay circuit
I = 2mA e1
I = 2 0.37 mA
mA
x = 74
For LR - decay circuit
I = 2mA e1
I = 2 0.37 mA
mA
x = 74
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This is a previous-year question from JEE Main 2021, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.