JEE Main 2023 — Alternating Current Question with Solution

The power delivered to the houses is given as 60 kW. This power is supplied at a voltage of 120 V. The power consumed in a resistive load can be found using the formula $P=V^2/R$, where P is the power, V is the voltage, and R is the resistance.

We can rearrange this formula to solve for the resistance:

$$R=V^2/P$$

Substituting the given values gives:

$$R=(120\text{V}{)}^2/60,000\text{W}=0.24\Omega$$

Since we want the resistance in milliohms (mΩ), we can convert this to milliohms by multiplying by 1000:

$$R=0.24\Omega \times 1000=240m\Omega$$

So, the value of resistive load required in the secondary circuit is 240 mΩ.