JEE Main 2024PhysicsAlternating CurrentMediumMCQ

JEE Main 2024 — Alternating Current Question with Solution

JEE Main 2024 (29 Jan Shift 2)

Question

In an a.c. circuit, voltage and current are given by: V=100sin(100t) V and I=100sin100t+π3 mA respectively. The average power dissipated in one cycle is :

Choose an option

Show full solutionCorrect option: C
Correct answer
C2.5 W

Step-by-step explanation

Standard expression of voltage is given by, V=V0sinωt and for current is given by, I=I0sinωt+ϕ. Clearly, ϕ is the phase difference here. From the given expression, ϕ=π3.

Average power dissipated in one cycle is given by,

 Pavg=VrmsIrmscos(ϕ)

=1002×100×10-32×cosπ3

=1042×10-3×12

=104=2.5 W

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About this question

This is a previous-year question from JEE Main 2024, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.