JEE Main 2021 — Alternating Current Question with Solution
From: JEE Main 2021 (Online) 26th February Morning Shift
Question
In a series LCR resonant circuit, the quality factor is measured as 100. If the inductance is increased by two fold and resistance is decreased by two fold, then the quality factor after this change will be __________.
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Show full solutionCorrect answer: 282.84
Correct answer
282.84
Step-by-step explanation
Quality factor =
Q' = 282.84
Q' = 282.84
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This is a previous-year question from JEE Main 2021, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.