JEE Main 2018 — Alternating Current Question with Solution
From: JEE Main 2018 (Online) 16th April Morning Slot
Question
A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5 A, and its efficiency is 90%, the output current would be ;
Choose an option
Show full solutionCorrect option: B
Correct answer
B45 A
Step-by-step explanation
Efficiency n = 0.9 =
as P = VI
Ps = 0.9 Pp
Vs Is = 0.9 Vp Ip
Is =
= 45 A
as P = VI
Ps = 0.9 Pp
Vs Is = 0.9 Vp Ip
Is =
= 45 A
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Alternating Current chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2018, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.