JEE Main 2020 — Alternating Current Question with Solution
From: JEE Main 2020 (Online) 7th January Morning Slot
Question
A LCR circuit behaves like a damped harmonic oscillator. Comparing it with a physical spring-mass damped oscillator having damping constant 'b', the correct equivalence would be:
Choose an option
Show full solutionCorrect option: C
Correct answer
CL m, C , R b
Step-by-step explanation
For spring mass damped oscillator
ma = - kx - bv
ma + kx + bv = 0
+ b + kx = 0 ....(1)
For LCR circuit
L + iR + = 0
L + R + = 0 .....(2)
Comparing (1) and (2), we get
L m, C , R b
ma = - kx - bv
ma + kx + bv = 0
+ b + kx = 0 ....(1)
For LCR circuit
L + iR + = 0
L + R + = 0 .....(2)
Comparing (1) and (2), we get
L m, C , R b
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This is a previous-year question from JEE Main 2020, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.