JEE Main 2026PhysicsAtomic PhysicsMediumMCQ

JEE Main 2026Atomic Physics Question with Solution

JEE Main 2026 (22 January Shift 2)

Question

The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly nm .

Choose an option

Show full solutionCorrect option: B
Correct answer
B1217

Step-by-step explanation

Smallest wavelength of lyman


for balmer series




paschen





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About this question

This is a previous-year question from JEE Main 2026, covering the Atomic Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.