JEE Main 2026 — Capacitance Question with Solution

A capacitor $P$ with capacitance $10\times 10^{-6}\mathrm{F}$ is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged capacitor $P$ is connected across another capacitor $Q$ with capacitance $20\times 10^{-6}\mathrm{F}$. The charge on capacitor $Q$ when equilibrium is established will be $\alpha \times 10^{-5}C$ (assume capacitor $Q$ does not have any charge initially), the value of $\alpha$ is $\_\_\_\_$。