JEE Main 2025 — Center of Mass Momentum and Collision Question with Solution
JEE Main 2025 (28 Jan Shift 2)
Question
A balloon and its content having mass is moving up with an acceleration ' '. The mass that must be released from the content so that the balloon starts moving up with an acceleration ' will be
(Take ' g ' as acceleration due to gravity)
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
$\begin{aligned} & F-m g=m a \\ & F=m a+m g \\ & F-(m-x) g=(m-x) 3 a \end{aligned}$ Put F $\begin{aligned} & \mathrm{Ma}+\mathrm{mg}-\mathrm{mg}+\mathrm{xg}=3 \mathrm{ma}-3 \mathrm{xa} \\ & \mathrm{x}=\frac{2 \mathrm{ma}}{\mathrm{~g}+3 \mathrm{a}} \end{aligned}$
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This is a previous-year question from JEE Main 2025, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.