JEE Main 2025 — Circular Motion Question with Solution
From: JEE Main 2025 (Online) 29th January Morning Shift
Question
A body of mass ‘m’ connected to a massless and unstretchable string goes in vertical circle of radius ‘R’ under gravity g. The other end of the string is fixed at the center of circle. If velocity at top of circular path is , where, n ≥ 1, then ratio of kinetic energy of the body at bottom to that at top of the circle is :
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This is a previous-year question from JEE Main 2025, covering the Circular Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.