JEE Main 2021PhysicsCommunication SystemEasyNumerical

JEE Main 2021 — Communication System Question with Solution

JEE Main 2021 (01 Sep Shift 2)

Question

A carrier wave with amplitude of 250  V is amplitude modulated by a sinusoidal base band signal of amplitude 150  V. The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is 50: x, then value of x, is _________.

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Show full solutionCorrect answer: 200
Correct answer
200

Step-by-step explanation

The value of maximum amplitude, Amax=Ac+Am=250+150 V=400 V
, and the value of minimum amplitude,Amin=Ac-Am=250-150 V=100 V
⇒AminAmax=100 V400 V=14=50200⇒x=200 V

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About this question

This is a previous-year question from JEE Main 2021, covering the Communication System chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.