JEE Main 2021PhysicsCurrent ElectricityMediumMCQ

JEE Main 2021 — Current Electricity Question with Solution

JEE Main 2021 (25 Jul Shift 2)

Question

The given potentiometer has its wire of resistance 10 Ω. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2 Ω resistor is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C409 V

Step-by-step explanation

20-V05+0-V05+20-V02=0

4+10=2 V05+V02

14=4 V0+5 V010

V0=1409Volt

Potential difference across 2 Ω resistor is 20-V0

That is 20-1409 V

Hence, answer is 409 Volt

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About this question

This is a previous-year question from JEE Main 2021, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.