JEE Main 2020 — Current Electricity Question with Solution
From: JEE Main 2020 (Online) 5th September Morning Slot
Question
A galvanometer of resistance G is converted
into a voltmeter of range 0 – 1 V by connecting
a resistance R1 in series with it. The additional
resistance that should be connected in series
with R1 to increase the range of the voltmeter
to 0 – 2 V will be :
Choose an option
Show full solutionCorrect option: C
Correct answer
CR1 + G
Step-by-step explanation
1 = ig(G + R1) ....(1)
2 = ig(R1 + R2 + G) ....(2)
Doing (1) (2), we get
R1 + R2 + G = 2R1 + 2G
R2 = R1 + G
2 = ig(R1 + R2 + G) ....(2)
Doing (1) (2), we get
R1 + R2 + G = 2R1 + 2G
R2 = R1 + G
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This is a previous-year question from JEE Main 2020, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.