JEE Main 2022PhysicsCurrent ElectricityEasyNumerical

JEE Main 2022 — Current Electricity Question with Solution

JEE Main 2022 (28 Jun Shift 1)

Question

A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of 15 Ω. The galvanometer G shows null defection when tapping key is at 43 cm mark from end A. If the end correction for end A is 2 cm, then the determined value of R will be Ω.

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Show full solutionCorrect answer: 19
Correct answer
19

Step-by-step explanation

Using the conditions of a balanced wheatstone bridge and adding the end correction.

15R=l+eL+e-l+e⇒1543+2=R102-45⇒R=5745×15

⇒R=19 Ω

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About this question

This is a previous-year question from JEE Main 2022, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.