JEE Main 2020 — Current Electricity Question with Solution
From: JEE Main 2020 (Online) 3rd September Evening Slot
Question
Two resistors 400 and 800 are connected in series across a 6 V battery. The potential difference measured by a voltmeter of 10 k across 400 resistor is close to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B1.95 V
Step-by-step explanation
V400 = i1 400
=
=
= 1.95 V
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.