JEE Main 2024PhysicsCurrent ElectricityEasyNumerical

JEE Main 2024 — Current Electricity Question with Solution

JEE Main 2024 (30 Jan Shift 1)

Question

Two cells are connected in opposition as shown. Cell E1 is of 8 V emf and 2 Ω internal resistance; the cell E2 is of 2 V emf and 4 Ω internal resistance. The terminal potential difference of cell E2 is ______ V.

Enter your answer

Show full solutionCorrect answer: 6
Correct answer
6

Step-by-step explanation

Current in circuit, I=8-22+4=66=1 A

Applying Kirchhoff's law from C to B,

VC-2-4×1=VB

⇒VC-VB=6 V

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.