JEE Main 2015PhysicsCurrent ElectricityMediumMCQ

JEE Main 2015 — Current Electricity Question with Solution

JEE Main 2015 (04 Apr)

Question



In the circuit shown, the current in the 1 Ω resistor is:

Choose an option

Show full solutionCorrect option: D
Correct answer
D0.13 A, from Q to P

Step-by-step explanation



R=3 Ω+2 Ω. Let potential at P=0, ∴VA=6 V, VD=−9 V, andVQ=x. Apply K.C.L. at x,  x−6 3 + x−0 1 + x+9 5 =0 . Solving, x=323  V. So, current in 1 Ω⇒i=323−01 from Q to P⇒i=0.13 A from Q to P

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About this question

This is a previous-year question from JEE Main 2015, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.