JEE Main 2018PhysicsCurrent ElectricityGalvanometer Voltmeter And AmmetermediumMCQ

JEE Main 2018 — Current Electricity Question with Solution

From: JEE Main 2018 (Online) 16th April Morning Slot

Question

In a circuit for finding the resistance of a galvanometer by half deflection method, a 6 V battery and a high resistance of 11 k are used. The figure of merit of the galvanometer is 60 division. In the absence of shunt resistance, the galvanometer produces a deflection of = 9 divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of is closest to :

Choose an option

Show full solutionCorrect option: D
Correct answer
D110

Step-by-step explanation

Current required by unit deflection is 60 A.

For, = 9 current is I = 9 60 A

I = 540 A = 540 106 A

Let G is resistance of galvanometer. Then,

[11000 + G] 90 106 = 1

99000 + 9G = 105

9G = 100000 99000

9G = 1000

Also, in half deflection method,

100 S = 11000 S = 110

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About this question

This is a previous-year question from JEE Main 2018, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.