JEE Main 2019PhysicsCurrent ElectricityWheatstone BridgeeasyMCQ

JEE Main 2019Current Electricity Question with Solution

From: JEE Main 2019 (Online) 10th January Evening Slot

Question

The Wheatstone bridge shown in figure, here, gets balanced when the carbon resistor used as R1 has the colour code (Orange, Red, Brown). The resistors R2 and R4 are 80 and 40, respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as R3, would be -

JEE Main 2019 (Online) 10th January Evening Slot Physics - Current Electricity Question 273 English

This question includes a diagram. The text above accompanies the figure.

Choose an option

Show full solutionCorrect option: A
Correct answer
ABrown, Blue, Brown

Step-by-step explanation

R1 = 32 10 = 320

for wheatstone bridge

  





  Correct answer is Brown  Blue  Brown

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About this question

This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.