JEE Main 2020PhysicsCurrent ElectricityPotentiometermediumNumerical

JEE Main 2020Current Electricity Question with Solution

From: JEE Main 2020 (Online) 7th January Evening Slot

Question

The balancing length for a cell is 560 cm in a potentiometer experiment. When an external resistance of 10 is connected in parallel to the cell, the balancing length changes by 60 cm. If the internal resistance of the ceil is , where N is an integer then value of N is .............

Enter your answer

Show full solutionCorrect answer: 12
Correct answer
12

Step-by-step explanation

Let the emf of cell is internal resistance is 'r' and potential gradient is x.

When only cell connected :

= 560x .....(1)

After connecting the resistor

= 500x ....(2)

from (1) and (2)

56 = 50 +5r

r = =

N = 12

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.