JEE Main 2021PhysicsCurrent ElectricityWheatstone BridgehardMCQ

JEE Main 2021Current Electricity Question with Solution

From: JEE Main 2021 (Online) 17th March Evening Shift

Question

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of 10V is maintained across AC.

JEE Main 2021 (Online) 17th March Evening Shift Physics - Current Electricity Question 203 English

This question includes a diagram. The text above accompanies the figure.

Choose an option

Show full solutionCorrect option: B
Correct answer
B4.87 mA

Step-by-step explanation







__________ (1)

Similarly,





__________ (2)

after solving equation (1) & (2)

VD = 0.79 volt

VB = 0.86 volt

Then the current through the galvanometer



= 4.87 mA

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.