JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 11th January Evening Slot
Question
A galvanometer having a resistance of 20 and 30 divisions on both sides has figure of merit 0.005 ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto 15 volt, is:
Choose an option
Show full solutionCorrect option: C
Correct answer
C80
Step-by-step explanation
Rg = 20
NL = NR = N = 30
FOM = = 0.005 A/Div.
Current sentivity = CS = =
gmax = 0.005 30
= 15 102 = 0.15
15 = 0.15 [20 + R]
100 = 20 + R
R = 80
NL = NR = N = 30
FOM = = 0.005 A/Div.
Current sentivity = CS = =
gmax = 0.005 30
= 15 102 = 0.15
15 = 0.15 [20 + R]
100 = 20 + R
R = 80
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This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.