JEE Main 2019PhysicsDual Nature of MatterEasyMCQ

JEE Main 2019 — Dual Nature of Matter Question with Solution

JEE Main 2019 (10 Apr Shift 1)

Question

In a photoelectric effect experiment, the threshold wavelength of light is 380 nm . If the wavelength of incident light is 260 nm , the maximum kinetic energy of emitted electrons will be
Given E (in  eV ) =1237λ(in nm)

Choose an option

Show full solutionCorrect option: C
Correct answer
C1.5 eV

Step-by-step explanation

From Einstein’s photoelectric equation,
K.Emax=hcλ-hcλ0 (here, λ0= threshold wavelength)
=1237260-1237380
=1237380-260380×260
=1.5 eV

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About this question

This is a previous-year question from JEE Main 2019, covering the Dual Nature of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.