JEE Main 2019PhysicsDual Nature of MatterMediumMCQ

JEE Main 2019 — Dual Nature of Matter Question with Solution

JEE Main 2019 (12 Jan Shift 2)

Question

When a certain photosensitive surface is illuminated with a monochromatic light of frequency ν, the stopping potential of the photo current is  -V02.  When the surface is illuminated by monochromatic light of frequency ν2, the stopping potential is -V0. The threshold frequency for photoelectric emission is

Choose an option

Show full solutionCorrect option: B
Correct answer
B3v2

Step-by-step explanation

hν​=W+V02e

hν​2=W+V0e

On solving, we get, W=32h ν​

⇒hν​0=32h ν​

⇒ν​0=32ν​

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About this question

This is a previous-year question from JEE Main 2019, covering the Dual Nature of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.