JEE Main 2023PhysicsDual Nature of MatterEasyMCQ

JEE Main 2023 — Dual Nature of Matter Question with Solution

JEE Main 2023 (30 Jan Shift 2)

Question

An electron accelerated through a potential difference V1 has a de-Broglie wavelength of λ. When the potential is changed to V2, its de-Broglie wavelength increases by 50%. The value of V1V2 is equal to :

Choose an option

Show full solutionCorrect option: B
Correct answer
B94

Step-by-step explanation

Let initial wavelength be λ, then after 50% increase wavelength will become 1.5λ.

Now, KE=P22m=eV & P=hλ

Therefore, eV=hλ22m.

So we can write

eV1=hλ22m   ...Eq(1) and 

eV2=h1.5λ22m   ...Eq(2)

From both equations, we get

V1V2=1.52=94

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About this question

This is a previous-year question from JEE Main 2023, covering the Dual Nature of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.