JEE Main 2026 — Electromagnetic Induction Question with Solution
JEE Main 2026 (06 April Shift 2)
Question
A square loop of side cm is placed in a time varying magnetic field with magnitude as Tesla. The normal to the plane of loop makes an angle of with the field. The maximum induced emf produced in the loop is __________ mV.
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Given:
Side of the square loop, cm m
Area of the loop, m
Magnetic field, T
Angle between the normal to the plane and the magnetic field,
The magnetic flux through the loop is given by:
Wb
By Faraday's law of induction, the induced emf is:
V
V
The maximum induced emf is the amplitude of :
V mV
Answer:
Side of the square loop, cm m
Area of the loop, m
Magnetic field, T
Angle between the normal to the plane and the magnetic field,
The magnetic flux through the loop is given by:
Wb
By Faraday's law of induction, the induced emf is:
V
V
The maximum induced emf is the amplitude of :
V mV
Answer:
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Electromagnetic Induction chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2026, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.