JEE Main 2019 — Electromagnetic Induction Question with Solution
From: JEE Main 2019 (Online) 10th January Evening Slot
Question
The self induced emf of a coil is 25 volts. When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is -
Choose an option
Show full solutionCorrect option: D
Correct answer
D437.5 J
Step-by-step explanation
J
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This is a previous-year question from JEE Main 2019, covering the Electromagnetic Induction chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.